Optimal. Leaf size=95 \[ -\frac {F^{c (a+b x)}}{2 e (d+e x)^2}-\frac {b c F^{c (a+b x)} \log (F)}{2 e^2 (d+e x)}+\frac {b^2 c^2 F^{c \left (a-\frac {b d}{e}\right )} \text {Ei}\left (\frac {b c (d+e x) \log (F)}{e}\right ) \log ^2(F)}{2 e^3} \]
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Rubi [A]
time = 0.05, antiderivative size = 95, normalized size of antiderivative = 1.00, number of steps
used = 3, number of rules used = 2, integrand size = 17, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.118, Rules used = {2208, 2209}
\begin {gather*} \frac {b^2 c^2 \log ^2(F) F^{c \left (a-\frac {b d}{e}\right )} \text {Ei}\left (\frac {b c (d+e x) \log (F)}{e}\right )}{2 e^3}-\frac {b c \log (F) F^{c (a+b x)}}{2 e^2 (d+e x)}-\frac {F^{c (a+b x)}}{2 e (d+e x)^2} \end {gather*}
Antiderivative was successfully verified.
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Rule 2208
Rule 2209
Rubi steps
\begin {align*} \int \frac {F^{c (a+b x)}}{(d+e x)^3} \, dx &=-\frac {F^{c (a+b x)}}{2 e (d+e x)^2}+\frac {(b c \log (F)) \int \frac {F^{c (a+b x)}}{(d+e x)^2} \, dx}{2 e}\\ &=-\frac {F^{c (a+b x)}}{2 e (d+e x)^2}-\frac {b c F^{c (a+b x)} \log (F)}{2 e^2 (d+e x)}+\frac {\left (b^2 c^2 \log ^2(F)\right ) \int \frac {F^{c (a+b x)}}{d+e x} \, dx}{2 e^2}\\ &=-\frac {F^{c (a+b x)}}{2 e (d+e x)^2}-\frac {b c F^{c (a+b x)} \log (F)}{2 e^2 (d+e x)}+\frac {b^2 c^2 F^{c \left (a-\frac {b d}{e}\right )} \text {Ei}\left (\frac {b c (d+e x) \log (F)}{e}\right ) \log ^2(F)}{2 e^3}\\ \end {align*}
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Mathematica [A]
time = 0.14, size = 88, normalized size = 0.93 \begin {gather*} \frac {F^{c \left (a-\frac {b d}{e}\right )} \left (b^2 c^2 (d+e x)^2 \text {Ei}\left (\frac {b c (d+e x) \log (F)}{e}\right ) \log ^2(F)-e F^{\frac {b c (d+e x)}{e}} (e+b c (d+e x) \log (F))\right )}{2 e^3 (d+e x)^2} \end {gather*}
Antiderivative was successfully verified.
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Maple [A]
time = 0.07, size = 155, normalized size = 1.63
method | result | size |
risch | \(-\frac {c^{2} b^{2} \ln \left (F \right )^{2} F^{b c x} F^{c a}}{2 e^{3} \left (b c x \ln \left (F \right )+\frac {\ln \left (F \right ) b c d}{e}\right )^{2}}-\frac {c^{2} b^{2} \ln \left (F \right )^{2} F^{b c x} F^{c a}}{2 e^{3} \left (b c x \ln \left (F \right )+\frac {\ln \left (F \right ) b c d}{e}\right )}-\frac {c^{2} b^{2} \ln \left (F \right )^{2} F^{\frac {c \left (a e -b d \right )}{e}} \expIntegral \left (1, -b c x \ln \left (F \right )-c a \ln \left (F \right )-\frac {-\ln \left (F \right ) a c e +\ln \left (F \right ) b c d}{e}\right )}{2 e^{3}}\) | \(155\) |
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Failed to integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A]
time = 0.36, size = 130, normalized size = 1.37 \begin {gather*} \frac {\frac {{\left (b^{2} c^{2} x^{2} e^{2} + 2 \, b^{2} c^{2} d x e + b^{2} c^{2} d^{2}\right )} {\rm Ei}\left ({\left (b c x e + b c d\right )} e^{\left (-1\right )} \log \left (F\right )\right ) \log \left (F\right )^{2}}{F^{{\left (b c d - a c e\right )} e^{\left (-1\right )}}} - {\left ({\left (b c x e^{2} + b c d e\right )} \log \left (F\right ) + e^{2}\right )} F^{b c x + a c}}{2 \, {\left (x^{2} e^{5} + 2 \, d x e^{4} + d^{2} e^{3}\right )}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \frac {F^{c \left (a + b x\right )}}{\left (d + e x\right )^{3}}\, dx \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Mupad [F]
time = 0.00, size = -1, normalized size = -0.01 \begin {gather*} \int \frac {F^{c\,\left (a+b\,x\right )}}{{\left (d+e\,x\right )}^3} \,d x \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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